Python: execute object

FYI. It does not raise an exception

It returns 1 or 0

0 = success
1 = failure

Hi just curious on the return code....

Is that the return code the result of calling the executeobject() function or the result of the package/transformation that was called?

For example of you call an existing package (eg. 1234) and that package fails then is the result of executeobject() 1 or 0? As opposed to trying to execute Package 1235 - that does not exist which I would imagine should return 1.

Thanks in advance

PS. I know I would run my own test but though the answer here may be helpful in the future when searching for executeobject() help.
cheers

It is the result of the package/transformation that was called.

I have updated the documentation.

www.etl-tools.com/wiki/advanced-etl-proc...cellaneous_functions

Thanks Peter.